java寻路代码 java迷宫寻路
求java实现矩阵图上任意两点的最短路径源码
我用的是递归调用方法，有个小问题就是在打印步数的时候是返向的，原因是就是程序不断的调用自己，到最后判断基值位准退出调用。这才开始从栈里取出方法进行执行的原因。
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代码欣赏：
public static int step = 1;
public static StringBuffer printStep = new StringBuffer();
public static int[][] maze ={{1,1,1,1,1,1,1,1,1,1,1},
{1,0,1,0,1,0,0,0,0,0,1 },
{1,0,1,0,0,0,1,0,1,1,1 },
{1,0,0,0,1,0,1,0,0,0,1 },
{1,0,1,1,0,0,1,0,0,1,1 },// 0代表可以通过，1代表不可通过
{1,0,1,0,1,1,0,1,0,0,1 },
{1,0,0,0,0,0,0,0,1,0,1 },
{1,0,1,0,1,0,1,0,1,0,1 },
{1,0,0,1,0,0,1,0,1,0,1 },
{1,1,1,1,1,1,1,1,1,1,1 } };
public static void main(String[] args) {
int i, j; //循环记数变量
Sample.way(1, 1);//二维数组起始值从下标1，1开始
System.out.println("起点从坐标 x = 1, y = 1开始");
System.out.println("终点坐标是 x = 8, y = 9结束");
System.out.println("这是迷宫图表");
System.out.println(" 0 1 2 3 4 5 6 7 8 9 10");
System.out.println(" +---+---+---+---+---+---+---+---+---+---+---+---+---+");
for(i = 0; i 10; i++){
System.out.print(" " + i + "‖");
for(j = 0; j 11; j++)
System.out.print("-" + maze[i][j] + "-‖");
System.out.println("");
System.out.println(" +---+---+---+---+---+---+---+---+---+---+---+---+---+");
}
//打印显示步数
System.out.print(printStep.toString());
}
public static boolean way(int x, int y){
if(maze[8][9] == 2)//代表递归终止条件（也就是当走出出口时标记为 2）
return true;
else{
if(maze[y][x] == 0){
maze[y][x] = 2;
/*
* 下面if判断条件代表当前坐标为基点，
* 根据判断对当前位置进行递归调用：如：
* 往上、往右上、往右、往右下、往下、
* 往左下、往左、往左上的坐标是否可走，
* 判断是否可走的返回条件是：
* 2代表可通过、1代表不能通过、3表示已经走过，但是未能走通。
*/
if(way(x, y - 1)){
printStep.append("第 " + step + " 步的所走的位置是 x = " + x + " y = " + y + "\n");
step++;
return true;
}else if(way(x + 1, y - 1)){
printStep.append("第 " + step + " 步的所走的位置是 x = " + x + " y = " + y + "\n");
step++;
return true;
}else if(way(x + 1 , y)){
printStep.append("第 " + step + " 步的所走的位置是 x = " + x + " y = " + y + "\n");
step++;
return true;
}else if(way(x + 1, y + 1)){
printStep.append("第 " + step + " 步的所走的位置是 x = " + x + " y = " + y + "\n");
step++;
return true;
}else if(way(x, y + 1)){
printStep.append("第 " + step + " 步的所走的位置是 x = " + x + " y = " + y + "\n");
step++;
return true;
}else if(way(x - 1, y + 1)){
printStep.append("第 " + step + " 步的所走的位置是 x = " + x + " y = " + y + "\n");
step++;
return true;
}else if(way(x - 1, y)){
printStep.append("第 " + step + " 步的所走的位置是 x = " + x + " y = " + y + "\n");
step++;
return true;
}else if(way(x - 1, y - 1)){
printStep.append("第 " + step + " 步的所走的位置是 x = " + x + " y = " + y + "\n");
step++;
return true;
}else{
maze[y][x] = 3;
return false;
}
}else
return false;
}
}
复制代码前需要楼主自己创建个 类
Sample.way(1, 1);这句代码是我的类的静态调用，改下XXXXX.way(1, 1);
XXXXX代表你创建的类。
下面是这个程序运行后的截图
Java 寻路算法,贪吃蛇，俄罗斯方块，连连看
这3个算法都不简单，给你写出完整代码，至少要一下午的时间，才10分，太实惠了吧
java 怎么使用navmesh
1 将你的地型、带有collider的模型等等资源设置为静态资源
2 使用烘焙，计算这些资源“能够行走的位置”
3 在需要寻路的人物或者其他单位上面加上navMeshAgent组件
4 使用代码进行寻路navMeshAgent中有setDestination();方法用于设定目标
求程序代码（java版的数据结构）
3个class，运行UI.java。
******
public class CircuitException extends Exception {public CircuitException(){}}
*****
import java.util.LinkedList;
public class GPS {
public static final int MAX = 65535;
public GPS(int maxSize){
graph = new Graph(maxSize);
}
public GPS(){
graph = new Graph();
}
public Graph graph;
public static void main(String args[]){
GPS gps = new GPS();
try {
gps.graph.addEdge("a", "b", 1);
gps.graph.addEdge("a", "c", 1);
gps.graph.addEdge("b","d" , 1);
gps.graph.addEdge("c","d" , 1);
gps.graph.addEdge("d","e" , 1);
gps.graph.addEdge("d","f" , 1);
gps.graph.addEdge("e","t" , 2);
gps.graph.addEdge("f","t" , 1);
LinkedList list = gps.graph.getPath("a", "d");
for(int i = 0 ; i list.size() ; i++){
System.out.print(list.get(i));
}System.out.println();
} catch (CircuitException e) {
System.out.println("出现了自环！");
}
gps.graph.showGraph();
System.out.println(gps.graph.gap);
}
public class Graph{
public int Zuidazhi = 50;
public int changdu = 0;
public Jiao[] vertex;
public double gap;
public Graph(){
vertex = new Jiao[Zuidazhi];
}
public Graph(int maxSize){
this.Zuidazhi = maxSize;
vertex = new Jiao[maxSize];
}
public void addVertex(String name){
vertex[changdu++] = new Jiao(name);
}
public void addEdge(String v1, String v2,double edge) throws CircuitException{
//先找到v1；
if(v1.equals(v2))
throw new CircuitException();
Jiao from = null;
Jiao to = null;
for(int i = 0 ; i changdu ; i++){
if(vertex[i].name.equals(v1)){
from = vertex[i];
}else if(vertex[i].name.equals(v2)){
to = vertex[i];
}
}
if(from == null){
this.addVertex(v1);
from = this.vertex[changdu-1];
}
if(to == null){
this.addVertex(v2);
to = this.vertex[changdu-1];
}//已经找到v1和v2；
//没有检测是否v1 v2边已经存在！
//加入边。
Jiao v1adj = new Jiao(v2);
v1adj.edge = edge;
Jiao v2adj = new Jiao(v1);
v2adj.edge = edge;
//添加联系
//检查联系是否已经存在
Jiao temp = from;
while(temp.next!=null){
Jiao temppar = temp;
temp = temp.next;
if(temp.name.equals(v1adj.name)){
temppar.next = temp.next;
}
}
v1adj.next = from.next;
from.next = v1adj;
//v2adj.next = to.next;
//to.next = v2adj;
}
//假设要找的必然存在，不用想是否不在
public LinkedList getPath(String v1 ,String v2){
int count = 0;
//System.out.println(count++);
boolean found[] = new boolean[changdu];
double distance[] = new double[changdu];
int to = 0;
Jiao from = null;
for(int i = 0 ; i changdu ; i++){
found[i] = false;
distance[i] = MAX;
}
for(int i = 0 ; i changdu ; i++){
if(vertex[i].name.equals(v1)){//找到始发地
from = vertex[i];
distance[i] = 0;
found[i] = true;
//System.out.println(count++);
}
if(vertex[i].name.equals(v2)){//找到目的地
to = i;
//System.out.println(count++);
}
}
//必须先准备好路径！
Jiao forCount = from;
int degree = 0;
while(forCount!=null){
degree++;
forCount=forCount.next;
}
LinkedList[] list = new LinkedList[degree];
int [] mark = new int[degree];
for(int i = 0 ; i degree ; i++){
list[i]=new LinkedList();
mark[i]=MAX;
}
int test=0;
int count2 = 0;
int count3 = 0;
//System.out.println(count+++"xx");
while(!found[to]test++100){
//System.out.println(count+++"FIRST");
//开始时from到所有都是最大值。
//找到标记了的节点
//找标记了的节点邻接的未标记的节点。
//得到最短的边，并标记。
//更新现有路径
double min = MAX;
int address = -1;
int father = -1;
for(int i = 0 ; i changdu ; i++){//对于已经找到的顶点寻找最小的往后的距离。
if(found[i]){//找到了的。
Jiao temp = vertex[i];
while(temp!=null){//vertex的邻接顶点~~
//先看temp的号码~
int tempNumber = -1;
for(int j = 0 ; j changdu ; j++){
if(vertex[j].name.equals(temp.name)){
tempNumber = j;
break;
}
}
if(!found[tempNumber]){//如果是还没有找到的~
double dist = distance[i]+temp.edge;
if(dist min){
min = dist;
father = i;
//System.out.println(" "+min);
address = tempNumber;
}
}
temp = temp.next;
}
}
}found[address] = true;
distance[address] = min;
//添加到已有路径中去！
//知道father
for(int i = 0 ; i degree ; i++){
if(list[i].isEmpty()||list[i].getLast().equals(vertex[father].name)){
list[i].addLast(vertex[address].name);
break;
}
}
}
for(int i = 0 ; i degree ; i++){
if(list[i].isEmpty())
continue;
else{
if(list[i].getLast().equals(v2)){
gap=0;
//先求出gap
Jiao pre = from;
Jiao nex = null;
for(int j = 0 ; j list[i].size() ; j++){
for(int k = 0 ; k changdu ; k++){
if(vertex[k].name.equals(list[i].get(j))){
nex = vertex[k];break;
}
}
while(pre.next!=null){//找到下一个的长度
pre = pre.next;
//System.out.println(nex.name +"nex.name");
if(pre.name.equals(nex.name)){
gap+=pre.edge;
//System.out.println(" gap2 "+gap);
}
}
pre = nex;
}
//System.out.println(gap+"gap");
return list[i];
}
}
}
return null;
}
public void showGraph(){
Jiao temp;
for(int i = 0 ; i changdu ; i++){
temp = vertex[i];
while(temp!=null){
System.out.print(temp.name+temp.edge+" ");
temp = temp.next;
}System.out.println();
}System.out.println("Show Over!");
}
}
public class Jiao{
public String name;
public Jiao next = null;
public double edge;
public Jiao(String name){
this.name = name;
}
}
}
******
import java.awt.EventQueue;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.util.LinkedList;
import javax.swing.JButton;
import javax.swing.DefaultListModel;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JList;
import javax.swing.JOptionPane;
import javax.swing.JScrollPane;
import javax.swing.JSeparator;
import javax.swing.JTextField;
import javax.swing.SwingConstants;
public class UI extends JFrame implements ActionListener{
private JTextField textField_5;
private JTextField textField_4;
private JList list_1;
private JList list;
private JTextField textField_1;
private JTextField textField_3;
private JTextField textField_2;
private JTextField textField;
private DefaultListModel model = new DefaultListModel();
private DefaultListModel model_1 = new DefaultListModel();
/**
* Launch the application
* @param args
*/
public static void main(String args[]) {
EventQueue.invokeLater(new Runnable() {
public void run() {
try {
UI frame = new UI();
frame.setVisible(true);
} catch (Exception e) {
e.printStackTrace();
}
}
});
}
/**
* Create the frame
*/
public UI() {
super();
setTitle("GPS寻路");
getContentPane().setLayout(null);
setBounds(100, 100, 500, 375);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
final JScrollPane scrollPane = new JScrollPane();
scrollPane.setBounds(11, 36, 221, 193);
getContentPane().add(scrollPane);
list = new JList(model);
scrollPane.setViewportView(list);
final JScrollPane scrollPane_1 = new JScrollPane();
scrollPane_1.setBounds(253, 36, 218, 193);
getContentPane().add(scrollPane_1);
list_1 = new JList(model_1);
scrollPane_1.setViewportView(list_1);
final JLabel label = new JLabel();
label.setText("从");
label.setBounds(10, 249, 24, 18);
getContentPane().add(label);
final JLabel label_1 = new JLabel();
label_1.setText("到");
label_1.setBounds(11, 273, 24, 18);
getContentPane().add(label_1);
textField = new JTextField();
textField.setBounds(50, 247, 103, 22);
getContentPane().add(textField);
textField_2 = new JTextField();
textField_2.setBounds(50, 271, 103, 22);
getContentPane().add(textField_2);
final JLabel label_2 = new JLabel();
label_2.setText("距离");
label_2.setBounds(11, 297, 37, 18);
getContentPane().add(label_2);
textField_3 = new JTextField();
textField_3.setBounds(50, 295, 103, 22);
getContentPane().add(textField_3);
final JButton button = new JButton();
button.setText("添加");
button.setBounds(155, 250, 73, 28);
getContentPane().add(button);
final JButton button_1 = new JButton();
button_1.setText("删除");
button_1.setBounds(155, 285, 73, 28);
getContentPane().add(button_1);
final JLabel label_3 = new JLabel();
label_3.setText("距离：");
label_3.setBounds(253, 297, 39, 18);
getContentPane().add(label_3);
textField_1 = new JTextField();
textField_1.setBounds(293, 295, 86, 22);
getContentPane().add(textField_1);
final JButton button_2 = new JButton();
button_2.setText("显示路径");
button_2.setBounds(385, 249, 86, 68);
getContentPane().add(button_2);
final JLabel label_4 = new JLabel();
label_4.setText("路径表示");
label_4.setBounds(11, 10, 66, 18);
getContentPane().add(label_4);
final JLabel label_5 = new JLabel();
label_5.setText("最佳路径");
label_5.setBounds(253, 12, 66, 18);
getContentPane().add(label_5);
//
button.addActionListener(this);
button_1.addActionListener(this);
button_2.addActionListener(this);
final JLabel label_6 = new JLabel();
label_6.setText("从");
label_6.setBounds(253, 249, 24, 18);
getContentPane().add(label_6);
textField_4 = new JTextField();
textField_4.setBounds(293, 247, 86, 22);
getContentPane().add(textField_4);
final JLabel label_7 = new JLabel();
label_7.setText("到");
label_7.setBounds(253, 273, 24, 18);
getContentPane().add(label_7);
textField_5 = new JTextField();
textField_5.setBounds(293, 271, 86, 22);
getContentPane().add(textField_5);
final JSeparator separator = new JSeparator();
separator.setOrientation(SwingConstants.VERTICAL);
separator.setBounds(239, 10, 8, 317);
getContentPane().add(separator);
}
@Override
public void actionPerformed(ActionEvent e) {
// TODO Auto-generated method stub
if(e.getActionCommand().equals("添加")){
try{String from = textField.getText();
String to = textField_2.getText();
if(from.equals(to)){
JOptionPane.showMessageDialog(null, "始点与终点不能相同");
return;
}
if(from.equals("")||to.equals("")){
JOptionPane.showMessageDialog(null, "添加不能为空");
return;
}for(int i = 0 ; i model.size() ; i ++){
if(model.get(i).toString().substring(0, model.get(i).toString().indexOf(":")).equals(
from+"-"+to))
model.remove(i);
}
double length = Double.parseDouble(textField_3.getText());
model.addElement(from+"-"+to+": "+length);
}catch(Exception e1){
JOptionPane.showMessageDialog(null, "距离为数字值");
}
}
if(e.getActionCommand().equals("删除")){
for(int i = 0 ; i model.size() ; i++){
if(list.isSelectedIndex(i))
model.remove(i);
}
}
if(e.getActionCommand().equals("显示路径")){
try{
model_1.removeAllElements();
GPS gps = new GPS();
String full,from,to;
double length;
for(int i = 0 ; i model.size() ; i++){
full = model.get(i).toString();
from = full.substring(0,full.indexOf("-"));
to = full.substring(full.indexOf("-")+2,full.lastIndexOf(":"));
length = Double.parseDouble(full.substring(full.indexOf(":")+1, full.length()-1));
//System.out.println(from);
//System.out.println(to);
try {
gps.graph.addEdge(from, to, length);
System.out.println(from +" "+ to);
} catch (CircuitException e1) {
System.out.println("有环存在");
}
}LinkedList list = gps.graph.getPath(textField_4.getText(), textField_5.getText());
model_1.addElement(textField_4.getText());
for(int i = 0 ; i list.size() ; i++){
model_1.addElement(list.get(i));
}//计算路径长度
textField_1.setText(""+gps.graph.gap);
}catch(Exception e1){
JOptionPane.showMessageDialog(null, "没有找到有关节点");
}
}
}
}
用java编写 深度优先法 寻路时 怎么实现八个方向的路径选择
//循环遍历八个方向：
for(int dx = -1; dx = 1; dx++) {
for(int dy = -1; dy = 1; dy++) {
//向x方向移动dx,向y方向移动dy
int nx = x+dx, ny = y + dy;
if()//这里是你要查找的满足条件的元素
}
}
Java 鼠标控制人物移动，地图随人物移动
去学习A星寻路，可以得到最短路径，其中也包括了绕开障碍物的代码，然后就是动画的图片切换了，如果说要地图跟随主角移动，那个应该是滚屏操作，也就是说你主角往右走，超过窗口或者屏幕（全屏）坐标一半的时候，地图整个往左移动，速度和主角的一样就出来效果了。如果你看不懂A星的话，那咂就给你一段BFS的C++语言代码，自己转换成JAVA代码写法（就是改些关键字，有不少经典的游戏算法都来自C/C++）就可以了，这个是简化版的A星寻路，一样可以找到最近的路径，你把path 这个路径记录下来再换算成像素位置就可以得到行走的具体步伐了...
#include "stdafx.h"
#include iostream
using namespace std;
const int rows = 10;//行数
const int cols = 10;//列数
const int nummax = 4;//每一步，下一步可以走的方向：4个
//四种移动方向(左、右、上、下)对x、y坐标的影响
//x坐标：竖直方向，y坐标：水平方向
const char dx[nummax] = {0,0,-1,1};
const char dy[nummax] = {-1,1,0,0};
//障碍表
char block[rows][cols] = {
0,1,0,0,0,0,0,0,0,0,
0,1,1,0,1,1,1,0,0,0,
0,0,0,0,0,0,0,0,0,0,
1,0,1,0,0,0,0,0,0,0,
0,0,0,0,0,0,1,1,1,0,
0,1,0,0,0,0,1,0,0,0,
0,0,0,0,0,0,1,1,0,1,
0,1,0,0,0,1,0,1,0,1,
0,1,1,1,0,0,0,1,0,1,
0,0,0,0,0,0,0,0,0,0,
};
char block2[rows][cols] = {
0,1,0,0,0,0,0,0,0,0,
0,1,1,0,1,1,1,0,0,0,
0,0,0,0,0,0,0,0,0,0,
1,0,1,0,0,0,0,0,0,0,
0,0,0,0,0,0,1,1,1,0,
0,1,0,0,0,0,1,0,0,0,
0,0,0,0,0,0,1,1,0,1,
0,1,0,0,0,1,0,1,0,1,
0,1,1,1,0,0,0,1,0,1,
0,0,0,0,0,0,0,0,0,0,
};
char path[rows][cols] = {0};//记录路径
int startX = 0,startY = 0;//起始点坐标
int endX = rows - 1,endY = cols - 1;//目标点坐标
//保存节点位置坐标的数据结构
typedef struct tagQNode{
char x,y;
int parentNode;//父节点索引
}QNode;
//打印路径
void printPath()
{
cout "" endl;
for (int i = 0;i rows;++i)
{
for (int j = 0;j cols;++j)
{
if (1 == path[i][j])
{
cout "♀";
}
else if(block2[i][j]==0)
cout "∷";
else if(block2[i][j]==1)
cout "■";
}
cout endl;
}
cout endl;
cout endl;
}
void BFS()
{
int num = rows * cols;
//利用数组来模拟队列
QNode *queue = (QNode *)malloc(num * sizeof(QNode));
//起始点入队列
queue[0].x = queue[0].y = 0;
queue[0].parentNode = -1;//起始点没有父节点
int front = 0,rear = 1;//队列的头和尾
while(front != rear)//队列不为空
{
for (int i = 0;i nummax;++i)
{
char nextX,nextY;//下一步的坐标
nextX = queue[front].x + dx[i];
nextY = queue[front].y + dy[i];
//下一个节点可行
if (nextX = 0 nextX rows nextY = 0 nextY cols 0 == block[nextX][nextY])
{
//寻找到目标点
if (nextX == endX nextY == endY)
{
//生成路径
path[nextX][nextY] = 1;
int ParIn = front;
while(ParIn != -1)
{
path[queue[ParIn].x][queue[ParIn].y] = 1;
ParIn = queue[ParIn].parentNode;
}
//printPath();
}
//入栈
queue[rear].x = nextX;
queue[rear].y = nextY;
queue[rear].parentNode = front;
++rear;
//标记此点已被访问
block[nextX][nextY] = 1;
}
}
++front;
}
free(queue);
}
int _tmain(int argc, _TCHAR* argv[])
{
BFS();
printPath();
system("pause");
return 0;
}
分享题目：java寻路代码 java迷宫寻路
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